On Thursday, Mr. Hansen continued to talk about the chain rule. The first thing we did in class is reviewed our homework. Number 9 was one we did together in class which was 1/(t^4+1)^3 and we were supposed to list the multiple functions in this function and use the chain rule to find the derivative. We started with finding the derivative of t^4+1 which is equal to 4t^3. Then we found the other function which was u^-3 and we found the derivative of this, -3u^-4 and then plugged in t^4+1 for u. We know that the chain rule is the product of these two derivatives so the answer for the total derivative is -3(t^4+1)*4t^3 which simplified to -12t^3/(t^4+1)^4. After going over this problem we worked on using the chain rule, but in a faster more efficient method. We were given a worksheet and did some problems off of it, focusing on using the chain rule quickly by kind of glancing at the functions and doing the work in our minds. Overall, it was another exciting day in the Math World of Calculus.
1 comment:
On Thursday, Mr. Hansen continued to talk about the chain rule. The first thing we did in class is reviewed our homework. Number 9 was one we did together in class which was 1/(t^4+1)^3 and we were supposed to list the multiple functions in this function and use the chain rule to find the derivative. We started with finding the derivative of t^4+1 which is equal to 4t^3. Then we found the other function which was u^-3 and we found the derivative of this, -3u^-4 and then plugged in t^4+1 for u. We know that the chain rule is the product of these two derivatives so the answer for the total derivative is -3(t^4+1)*4t^3 which simplified to -12t^3/(t^4+1)^4. After going over this problem we worked on using the chain rule, but in a faster more efficient method. We were given a worksheet and did some problems off of it, focusing on using the chain rule quickly by kind of glancing at the functions and doing the work in our minds. Overall, it was another exciting day in the Math World of Calculus.
Post a Comment